5x^2+35=40x

Solution for 5x^2+35=40x equation:

5x^2+35=40x

We move all terms to the left:

5x^2+35-(40x)=0

a = 5; b = -40; c = +35;
Δ = b2-4ac
Δ = -402-4·5·35
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-30}{2*5}=\frac{10}{10}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+30}{2*5}=\frac{70}{10}
=7
$